3x^2+9x+64-2x^2+25x=0

Solution for 3x^2+9x+64-2x^2+25x=0 equation:

3x^2+9x+64-2x^2+25x=0

We add all the numbers together, and all the variables

x^2+34x+64=0

a = 1; b = 34; c = +64;
Δ = b2-4ac
Δ = 342-4·1·64
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-30}{2*1}=\frac{-64}{2}
=-32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+30}{2*1}=\frac{-4}{2}
=-2
$